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// PR c++/16405
// { dg-options "-O2" }
// { dg-do run }
// There should be exactly one temporary generated for the code in "f"
// below when optimizing -- for the result of "b + c". We have no
// easy way of checking that directly, so we count the number of calls
// to "memcpy", which is used on (some?) targets to copy temporaries.
// If there is more than two calls (one for coping "*this" to "t", and
// one for copying the temporary to "a"), then there are too many
// temporaries.
int i;
extern "C"
void *memcpy (void *dest, const void *src, __SIZE_TYPE__ n)
{
char *d = (char *) dest;
const char *s = (const char *) src;
while (n--)
d[n] = s[n];
++i;
return dest;
}
struct T {
int a[128];
T &operator+=(T const &v) __attribute__((noinline));
T operator+(T const &v) const { T t = *this; t += v; return t; }
};
T &T::operator+=(T const &v) {
return *this;
}
T a, b, c;
void f() { a = b + c; }
int main () {
i = 0;
f();
if (i > 2)
return 1;
}
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